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		<title>Bài toán tính tổng S = 1^3+2^3+3^3+&#8230;+n^3</title>
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		<dc:creator><![CDATA[Nguyễn Tấn Linh]]></dc:creator>
		<pubDate>Thu, 16 May 2019 10:36:46 +0000</pubDate>
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					<description><![CDATA[Bài toán được viết dưới dạng đề khác là chứng minh: \[{1^3} + {2^3} + {3^3} + ..{n^3} = {(1 + [&#8230;]]]></description>
		
		
		
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			<media:title type="plain">Bài 6: Tính tổng dãy lũy thừa cùng số mũ</media:title>
			<media:description type="html"><![CDATA[Bài 6: Tính tổng dãy lũy thừa cùng số mũ]]></media:description>
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		<title>Chứng minh rằng (a+b+c)^3 = a^3 + b^3 + c^3 + 3.(a + b)(b + c)(c + a) bằng 4 cách</title>
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		<dc:creator><![CDATA[Nguyễn Tấn Linh]]></dc:creator>
		<pubDate>Wed, 15 May 2019 04:41:05 +0000</pubDate>
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					<description><![CDATA[Chứng minh rằng (a+b+c)^3 = a^3 + b^3 + c^3 + 3.(a + b)(b + c)(c + a) với mọi [&#8230;]]]></description>
		
		
		
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			<media:title type="plain">Chứng minh: (a+b+c)^3 = a^3 + b^3 + c^3 + 3(a+b)(a+c)(b+c)</media:title>
			<media:description type="html"><![CDATA[Toán. Chứng minh biểu thức:(a+b+c)^3=a^3+b^3+c^3+3(a+b).(a+c).(b+c)]]></media:description>
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		<title>Bài toán chứng minh 1^2+2^2+3^2+&#8230;+n^2 = n.(n+1).(2n+1)/6</title>
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		<dc:creator><![CDATA[Nguyễn Tấn Linh]]></dc:creator>
		<pubDate>Sun, 12 May 2019 13:29:00 +0000</pubDate>
				<category><![CDATA[Bài toán hay]]></category>
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					<description><![CDATA[Chứng minh \[{1^2} + {2^2} + &#8230; + {n^2} = \frac{{n(n + 1)(2n + 1)}}{6}\] Đây là một bài toán [&#8230;]]]></description>
		
		
		
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			<media:title type="plain">Tính tổng các lũy thừa cùng số mũ. Toán nâng cao lớp 6,7</media:title>
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